----- Original Message -----
From: "Ling F. Zhang" <[EMAIL PROTECTED]>
Date: Tuesday, July 1, 2003 7:04 am
Subject: math stuff...

> okay...I am glad @ how easy it is to use perl scalar
> both as numerical value and string...but sometimes I
> just need to do integer division the C way:

sure, you can use perl's int function.BTW in the posix module there is floor and ceil 
as well.

perldoc -f int

HTH,
Mark G
> 
> when 10/3, I want it to equal to 3, not 3.33333....
> is there an operator for such operation? or do I have
> to do like:
> $a=10
> $b=3
> $c=$a/$b; # c=3.33333....
> $d=$c-$a%$b/$b; # d =3
> 
> or a one-liner:
> $d = ($a - $a % $b)/%b;
> 
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