On Jun 10, James Edward Gray II said: >s/\\([A-Za-z0-9]+?) \[(\d+?)\]/$1\[$2]/;
There's no reason NOT to capture the brackets. Also, the non-greediness you've supplied is useless, since there's no way for them to match too much. After the [A-Za-z0-9] is a space, which is NOT matchable by [A-Za-z0-9], and after the \d there is a ], which can't be matched by \d. s/\\([a-zA-Z0-9]+) (\[\d+\])/$1$2/g; I might even go so far as to say s/\\([a-zA-Z0-9]+) (?=\[\d+\])/$1/g; -- Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/ RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/ <stu> what does y/// stand for? <tenderpuss> why, yansliterate of course. [ I'm looking for programming work. If you like my work, let me know. ] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
