Thanks John, it is clear enough.
regards Jair ----- Original Message ----- From: "John W. Krahn" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Monday, June 16, 2003 10:59 AM Subject: Re: Is empty directory? > Jair Santos wrote: > > > > Thank to Mark , Rob and Charles for your help. > > > > I am using the following snippet of code to check if the directory is empty > > and it is working. But I still cannot understand the line my $count = () = > > readdir $dh; > > > > Can anybody explain whats the use of the = ( ) = ? > > readdir() returns a list in list context or a scalar in scalar context. > In order to get the number of files you have to assign the list from > readdir() to an array and then use that array in scalar context to get > the number of elements of that array. > > my @array = readdir $dh; > my $count = @array; > > But perl has a shortcut that allows you to assign a list to () which in > scalar context returns the number of elements in the list without having > to create an array. > > # with explicit array > my $count = my @array = readdir $dh; > > # perl shortcut with no array > my $count = () = readdir $dh; > > > John > -- > use Perl; > program > fulfillment > > -- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
