Deborah wrote: > > How does Perl interpret a string when used in a numeric comparison > equation? > I accidently used a numeric comparison operator when I was comparing > strings and I found that no matter what strings I compared, Perl always > said they were equal. > > Any other operation (such as <, >, != ) always proved false, but it was > always true that 'stringA'=='Bstrg'. Is it just saying that "it is > true" that stringA and Bstrg are both strings? I thought it would count > spaces or convert to numbers or something like that. Well, actually, I > first was surprised that it didn't give me an error since I used the > wrong type of operator. What is it doing in this case?
It depends on what is in the string: $ perl -le' print "string" + 0; print " 8 is a number" + 0; print " 1e1 " + 0; print "oops 8" + 0; ' 0 8 10 0 If perl can convert the leading characters to a number then it will, otherwise the string has the numeric value of zero. John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
