James,
I hope this is my last question. I appreciate your
(and everyone else's that has contributed)
generousity.
I have a web site I inherited where a single page has
3000 lines of perl code. It does not use strict or
warnings. The original authors only used global
variables and never used any function arguments.
So I needed to pass arrays as function arguments (to
keep my sanity) so here is what I did (see below). It
seems to work. Since I am passing an array by
reference, I am using @$ to dereference the function
parameter. That makes sense to me.
Did I do it wrong? (see below). I'm beginning to think
so.
Why does "@$y[$i]" work here, and "foreach $i (keys
%$x)" works to fetch the keys from a reference to a
hash, but I use $$x{$i} to fetch hash reference
element values instead of %$x{$i}?
This seems very inconsistent to me.
sub print_array {
my ($y, $n) = @_;
for my $i ( 0 .. $#$y ) {
print "print_array using .. y[$i] = @$y[$i]\n";
}
}
# It was not my idea to use undeclared variables!
# Are we creating a reference to a hash here?
$undeclared[0] = 'a';
$undeclared[2] = 'b';
$undeclared[3] = 'c';
&print_array([EMAIL PROTECTED], 3);
Thanks,
Siegfried
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