> my $i = 1;
> do {print "$i\n"; $i++;} while $i < 1;
> print $i . "\n";
Be aware that the above is different from
my $i = 1;
print $i++."\n" while $i < 1;
print $i . "\n";
because a do{}while() always goes through the do{} *at least once*.
If that was overstating the otherwise horrifically obvious, I
apologize. :)
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