Dan Muey wrote: > > IS there a better way to perhaps assign the value of $1 back to $var all in one >statement?
Yes. > EG > > $var = 'hello.domain.com'; > # Instead of this :: > $var =~ m/((\w+)\.(\w+)$)/; # $1 then becomes 'domain.com' > $var = $1; # then $var becomes 'domain.com' > # Perhaps a one liner version? > > I know there's a way but it's Monday :( ($var) = $string =~ /(\w+\.\w+)$/; Note that you need the parenthesis around $var to force list context because the result of a match in scalar context returns 'true' or 'false'. John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
