$query = "SELECT ad_id, text_extra, life FROM help_wanted WHERE ad_id in(".join(',', @id_set).")";
On Saturday, November 23, 2002, at 08:30 PM, Mariusz wrote:
I sent the following mysql query and got an error:(
SELECT ad_id, text_extra, life FROM help_wanted WHERE ad_id in(@id_set)
It prints correctly as:
SELECT ad_id, text_extra, life FROM help_wanted WHERE ad_id in(20 19 14)
but the whole idea doesn't work; what am I missing?
Mariusz
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