On Oct 15, Rob said:
>From: "chad kellerman" <[EMAIL PROTECTED]>
>
>> $hits{$hour} = $hits{$hour}+1;
[snip]
>> $hits{$hour} = $hits{$hour}+1;
>>
>> What it the best way to create a counter?
>>
>> I have seen $var++, it would not work here I had to use +1.
>
>But I'd be interested to know why you had to use '+ 1'?
You are misinterpreting Chad's problem. Chad didn't show EXACTLY the ++
code he used, but I think I know. Chad originally tried:
$hits{$hour} = $hits{$hour}++;
but it did not work. Why? Because $hits{$hour}++ returns the PREVIOUS
value of $hits{$hour} (0 in this case), then increments it by 1. BUT then
$hits{$hour} gets set back to 0 (the returned value).
Chad, you do not need to assign to $hits{$hour} again. Simply saying
$hits{$hour}++;
or, more computer-scientifically,
++$hits{$hour};
is sufficient.
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
<stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
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