Hello everyone, The following is from page 75 in the Camel:
"List assignment in scalar context returns the number of elements produced by the expression on the <i>right</i> side of the assignment: $x = ( ($a, $b) = (7,7,7) ); #set $x to 3, not 2 ...." It goes on to explain how this is useful but from previous reading in the same section I don't understand how or why this works. When I first saw this, I worked out the assignment where $a and $b each get a 7 and the third 7 is discarded, then $x gets the last value in the list of $a and $b because of the comma operator for list literals in a scalar context...or does the presence of vars in the list mean that this isn't a list literal, more like an array in behavior? So really, I guess I don't understand either side of the assignment and how it behaves in scalar context due to $x. :) So I guess this could end up being something I just memorize, but I'd rather understand what's happening... Sorry if this was confusing. TIA, Nathanael -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
