That is okay, I dont want to do that way. I want to write
stronger regular expressions.
I would like to know if my regular expressions are correct.
further, when I write something like /((a|A)(b|B))/g
For aB I am getting, $1 = aB, $2 = a, $3 = B.
and $4,5,6 .. have the next occurrences. But I do not want
a or B, only aB's. I cannot remove inner parentheses as it
would be /(a|Ab|B)/ which is not what I want.
Is my problem clear?
>From: Timothy Johnson <[EMAIL PROTECTED]>
>To: "'Rum Pel'" <[EMAIL PROTECTED]>, [EMAIL PROTECTED]
>Subject: RE: grouping regex match return values
>Date: Wed, 18 Sep 2002 01:06:57 -0700
>
>
>How about this?
>
>while($_ =~ /(\d{1,2}\/\d{1,2}\/\d{4})/g){
> push @q,$1;
>}
>
>Perl assigns the variable $1 to the first match in parentheses. ($2 for the
>next match within the same regex, and so on)
>
>
>The regex above matches:
>
> One or two digits \d{1,2}
> followed by
> a backslash \/
> followed by
> one or two digits \d{1,2}
> followed by
> a backslash \/
> followed by
> four digits \d{4}
>
>-----Original Message-----
>From: Rum Pel [mailto:[EMAIL PROTECTED]]
>Sent: Tuesday, September 17, 2002 9:18 PM
>To: [EMAIL PROTECTED]
>Subject: grouping regex match return values
>
>
>
>I want to pick dates from a file, I did it the following way:
>-----
>$day = "([12]?[0-9]|30|31)";
>$weekday = "(Mon|Tue|Wed|Thu|Fri|Sat|Sun)";
>$month =
>"([1-9]|10|11|12|Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)";
>$year = "(1999|2000|2001|2002)";
>
>$query = "$month\/$day\/$year";
>
>@q = "Today is Tue 9/17/2002 Tomorrow is 10/17/2002?" =~ /$query/g;
>print "q = " . Dumper(@q);
>-----
>
>Now, the array q has 6 values - 9, 17, 2002, 10, 17, 2002.
>Instead I want two values only - "9/17/2002", "10/17/2002"
>
>do i need to rewrite my query?
>
>
>
>
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