Than its possible: my $x = 0; > my @arr1 = (1, 2, 3); > my @arr2 = (4, 5, 6); > my @arr3 = (7, 8, 9); > my @arrofarrs; > unshift (@arrofarrs, \@arr3); > unshift (@arrofarrs, \@arr2); > unshift (@arrofarrs, \@arr1); unshift (@arr1, $x);
and it will be in @arrofarrs. right? > -----Ursprüngliche Nachricht----- > Von: Sudarshan Raghavan [mailto:[EMAIL PROTECTED]] > Gesendet am: Mittwoch, 28. August 2002 23:23 > An: Perl beginners > Betreff: Re: How to unshift to an array in an array of arrays? > > On Wed, 28 Aug 2002, Angerstein wrote: > > > How to unshift to an array in an array of arrays? > > Something like this > my @arr1 = (1, 2, 3); > my @arr2 = (4, 5, 6); > my @arr3 = (7, 8, 9); > my @arrofarrs; > unshift (@arrofarrs, \@arr3); > unshift (@arrofarrs, \@arr2); > unshift (@arrofarrs, \@arr1); > > An array of arrays is an array of references to arrays. In effect > you will > be unshifting the reference to the new array into your array of arrays. > > > -- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
