<[EMAIL PROTECTED]> wrote: > I have a string that looks like > > Operator Overview#PGM#Report about all configured > operators#/opt/OV/bin/OpC/call_sqlplus.sh all_oper# > > I want to replace the last "#" with a newline. I've come up with a few ideas > like > > substr ($_, rindex ($_, "#"), 1) = "\n" ; > or > substr ($_, length ($_) - 1, 1) = "\n" ; > or > chop ; $_ .= "\n" ; > > Are there any better ways, maybe using s/// or tr/// ? TIA... >
This is horrible, but works :) s/(.+)#(.+)$/$1\n$2/ It will always match greedy, so it will always match the last # on the line :) Tor -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
