Chris -- ...and then chris said... % % I have two variables (@array1 and @array2). @array1 will be % initialized with a list of values. Is it possible to declare @array2 % in such a way that it will reference @array1?
Do you want @array2 to be a *copy* of @array1 when this is all done, or should it actually reference @array1 so that changes to "one of them" force changes is "the other"? You've seen how to make a reference (the *array2 thing). If you want an identical but unique copy, something like bash-2.05a$ perl -e ' @a1 = qw ( some values here ) ; @a2 = @a1 ; print "a1: $a1[1] a2: $a2[1]\n" ; $a2[1] = "other" ; print "a1: $a1[1] a2: $a2[1]\n" ; ' a1: values a2: values a1: values a2: other might do you nicely. % % I am trying to avoid looping through the elements and copying over. That's easy; just set @a2 = @a1 and you have a copy. No loop-writing necessary :-) HTH & HAND :-D -- David T-G * It's easier to fight for one's principles (play) [EMAIL PROTECTED] * than to live up to them. -- fortune cookie (work) [EMAIL PROTECTED] http://www.justpickone.org/davidtg/ Shpx gur Pbzzhavpngvbaf Qrprapl Npg!
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