I'm an expert perl programmer who is totally baffled by this very simple problem that seem like there must be an obvious solution that I dont know about. can any one help me
as you know, when a perl command runs the arguments on the command line are split on whitespace and placed in @ARGV What I want instead is to know the exact input command line, before it is split on white space. You might think, "well just join the @ARGV array and voila!: but this is not exactly the same thing. the main differtence is that perl removes any surrounding quotation marks of the split arguments. I want to capture the exact command line with quotes. THE QUESTION: There must be some magic perl cpan lib or maybe some magic perl variable that can access this string; where is it?? here is a trivialized example to help make this clear @ARGV is the same for the following two very different lines func.pl ls "-l" func.pl ls -l suppose that what func.pldis was simply exec(the command line). exec-ing the string ls -l is not the same as execing the string ls "-l" in the former case -l is an arg to the "ls" function while in the latter the it is looking for a file name that happens to be called "-l" (yes a stupid name, but this is a trivial example). Another case comes up when the embedded string contains white space or embedded quotations: you dont know whether the surrounding quotations were single or double quotes since @ARGV removes them. but this matters when you go to reconstruct the string from the bare arguments in @ARGV ls "spam in a can" is not the same as ls spam in a can and ls "a quote ' mark" versus ls 'a quote ' mark' verus ls a quote ' mark obviously quotemeta can help out here but is not a panacea. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
