Hey u posted yours many times
cut paste the code below ( you may have to install Time::ParseDate , and POSIX You can avoid POSIX if you can use the localtime directly #!/usr/bin/perl use Time::ParseDate; use POSIX qw(strftime); $ARGV[0]=~s/^(.*?)(\d\d:\d\d:\d\d).*$/$2 $1/; print strftime "%d/%m/%Y %H:%M", localtime(parsedate($ARGV[0])); Chris Knipe wrote: > Lo all, > > How can I convert a date such as '18 Jun, 2002 at 11:00:00 (SAT)' into a > DD/MM/YYYY HH:MM string? > > I've been on google for quite some time now, and looked at quite a few CPAN > stuff, but I can't seem to find anything converting that specific format? > > -- > me > > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]