Drieux wrote: > > On Friday, May 24, 2002, at 08:13 , Ankit Gupta wrote: > > > I am working on a project in which I need to get Date part of > > below written header. I am trying to use Regular expression to extract > > Date: > > line. I am able to achieve everything after the Date: word but not only > > that > > line. I mean to say that I need only this string Thu, 23 May 2002 19:47:50 > > +0530 . Can someone help me in this. I am trying > > $header =~ m/Date:/; and then my $ab = " $' \n"; but this gives me > > everything after Date: word. As I wrote above, I need only Thu, 23 May > > 2002 > > 19:47:50 +0530 string > > we did a similar problem trying to grovel out the Proxy-Auth: > > http://www.wetware.com/drieux/pbl/RegEx/parseProxyAuth.txt > > the simplest solution would be > > $header =~ m/Date:\s*([^\n]+)/; ^^^^^^ [^\n]+ is the same as .+ because the period (.) does not match a newline unless you are using the /s modifier.
> my $dtg = $1; You should test that the regular expression matched successfully before using the numeric scalar variables. John -- use Perl; program fulfillment -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
