On Apr 26, Tara Calishain said: >I need to back up two days from localtime and I can't figure out how to do >it. Currently I'm doing this just so I can work out the rest of the program: > >($day, $month, $year) = (localtime) [3,4,5]; #getting your local time
The generic (read: potentially unsafe) way is to fix the problem right there: ($day, $month, $year) = (localtime(time - 86400*2))[3,4,5]; The only place to worry about this is during the switch to/from Daylight Savings Time, at 2:00 am, twice a year. -- Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/ RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/ ** Look for "Regular Expressions in Perl" published by Manning, in 2002 ** <stu> what does y/// stand for? <tenderpuss> why, yansliterate of course. [ I'm looking for programming work. If you like my work, let me know. ] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
