Actually, \n's are the one thing that the $ anchor doesn't work exactly
right on. Usually it's not a huge deal, but Perl will still match a line
that has a \n after the part that you are trying to match if you use $ to
anchor. This is normally very useful, as in the case of a line of text
being read from a file. Without this behavior you would have to put a \n at
the end of all of your regexes. So:
$radentry =~ /\n\n$/;
will match "\n\n" and "\n\n\n"
To fix this problem, you should remember the \Z anchor, which matches only
the end of a string.
$radentry =~ /\n\n\Z/;
-----Original Message-----
From: Kevin Cornmell
To: '[EMAIL PROTECTED]'
Sent: 4/24/02 2:45 AM
Subject: RE: Patterm Matching
++++++++++++++++++++++++++++++++++++++++++++++++++
Please read the disclaimer at the bottom of this e-mail.
++++++++++++++++++++++++++++++++++++++++++++++++++
Or try anchoring that regex.
if ($radentry =~/\n\n$/){
foo;
}
-----Original Message-----
From: John W. Krahn [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, April 24, 2002 10:42 AM
To: [EMAIL PROTECTED]
Subject: Re: Patterm Matching
Andrew Tait wrote:
> Hi All,
Hello,
> Quick question. How can I check if the last two characters of a string
are
> both new line's (i,e, \n)
>
> This is what I have come up with so far:
>
> if ($radentry =~ /"*\n\n/")
if ( substr( $radentry, -2 ) eq "\n\n" )
John
--
use Perl;
program
fulfillment
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