The return value of rand() is a random number between 0 and the optional
argument (1 by default).
In this case there are 6 elements in the array, so we want a number between
0 and 5. So try this variation on your code:
@tea = ("Meba", "Shaun", "Mark", "Jason", "Rick", "Dan");
$get = int(rand(6));
print $get;
$who = $tea[$get];
$affirm = "The lucky tea maker is ";
$result = $affirm.$who;
$fail = "Sorry I wasn't listening. Try again!\n";
if (defined($tea[$get])){
print $result
}else{
print "$fail"
}
-----Original Message-----
From: Wytch [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, March 27, 2002 3:26 PM
To: [EMAIL PROTECTED]
Subject: random word from array
I decided to write a little script to help choose who will make the tea on
our gaming night [there is always an argument!]
I thought I was doing quite well but it seems I am picked on by the
[non]random script I wrote! It seems to default to the first word in the
array.
I used rand @array;
I think perhaps that I am thinking about it too simply and perhaps I need to
involve more math - but I am not good at maths [though I am willing and a
quick learner...lol] ! so can anyone point me in the right direction?
#!c:/perl/perl.exe
@tea = "Meba", "Shaun", "Mark", "Jason", "Rick", "Dan";
#below is the problem area I think - perhaps rand is not appropriate here?
#or I haven't phrased it right?
#I have looked through masses of documentation and faqs but can't find a
thing.
#Am I blind or just dim?
$get = rand @tea;
$who = $tea[$get];
$affirm = "The lucky tea maker is ";
$result = $affirm.$who;
$fail = "Sorry I wasn't listening. Try again!\n";
print "Enter y to see who will make the tea: ";
$input = <STDIN>;
chomp $input;
if ($input eq "y") {
$a= true;
}
if ($a) {print $result
}
else
{
print "$fail" };
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