Hi Matthew, First of all, subtracting scalars is perfectly valid, so the actual error must be something else. Here are three things you should check.
1) First, you don't have a semicolon at the end of that line. 2) Second, if you are operating under 'use strict', you will need to predeclare your variables before using them so, (assuming that $dif and $score were declared elsewhere): my $need = $dif - score; 3) A "500 server error" implies that you are writing a CGI. I can't tell based on what you've said, but I think the most likely thing that is happening here is that, somehow, what you are generating invalid HTML and your web server is spitting up on the results...in other words, this is a CGI error, not actually an arithmetic error. HTH, Dave On Sun, 24 Mar 2002, Matthew Harrison wrote: > I have two scalars created from passed params. i want to create a third > variable by subtracting the two scalars. how can i do this? i have tried: > > $need = $dif - $score > > but i get a 500 server error and my error log says that i cannot use the > '-' operator on a scalar variable. can anyone suggesta better way? > > cheers > > -- > Matthew Harrison > Internet/Network Services Administrator > Peanut-Butter Cheesecake Hosting Services > Genstate > www.peanutbuttercheesecake.co.uk > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
