> Thanks. I got lots to learn about perl, thinking
> for the 2 hours I was trying to solve my issue
> with chomp and split. I have began disecting your
> reponse to learn from it. One question, the last
> print statement:
>
> print $_ . "\n";
since ($Jonathan eq "Fool") {
Opps... I've abondoned my common sense and
Perl knowledge to give you something erroneous.
This thinking about being safe applies to regex's
but not print.
}
> what is the significance of the . ? when I
> remove it nothing is displayed
On the shebang, make sure you have:
#!perl -w
as otherwise you won't get your warnings.
The . means concatonate, that is, join strings
together.
If you had:
my $Boy = "Jack";
my $Girl = "Gill";
my $sentence = $boy . " and " . $Girl . " went up " .
"the hill to fetch a pail of water\n";
print $sentence;
Of course in this instance you can place that in
double quotes, but occasionally this way is more
appropriate.
Since we are talking about . , you might also be
interested in join:
my $sentence = join " ", $Boy, 'and', $Girl, 'went up',
"the hill to fetch a pail of water\n"
which just takes an array, and joins it together using
the first string - which I gave as a single space.
Take care,
Jonathan Paton
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