On Feb 9, Matt C. said:
> my @array=split; #split on space by default
> $HASH{ $array[0] } = @array[1,2];
>
> # Above is the slice. Notice the @arry[1,2]; it's in array context.
No, it's in scalar context.
$x = @array[1,2];
is like
$x = ($array[1], $array[2]);
which sets $x to $array[2]. Maybe you want
$HASH{ $array[0] } = "@array[1,2]";
By putting @array[1,2] in a string, it acts like
"$array[1] $array[2]"
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Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
<stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
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