From: sfritz <[EMAIL PROTECTED]>
> having two
>
> my $name = "Sean Fritz";
> my $name = "Sean W. Fritz"; #functions as the shown assignment
> statment,
>
> just functions as an assignment statment (I believe) and dosen't
> alocate any memory or destroy the previous variable. I could be very
> wrong on that part though.
Try this script :
#!perl
my $x = 5;
$r = \$x;
print "REF: $r\n";
my $x = $x;
$r = \$x;
print "REF: $r\n";
__END__
You can see that the second my() does create a new variable ...
and masks the previous one.
> I do know that
>
> my $a = $a; #refrences whatever was the scoped $a before
>
> will refrence whatever $a was prior to you creating that global var.
It will get a copy, not reference the original value :
my $x = 'Hello World';
$r1 = \$x;
my $x = $x;
print "Orig: $$r1\nNew: $x\n\n";
$x = 'Hi dude';
print "Orig: $$r1\nNew: $x\n\n";
Jenda
=========== [EMAIL PROTECTED] == http://Jenda.Krynicky.cz ==========
There is a reason for living. There must be. I've seen it somewhere.
It's just that in the mess on my table ... and in my brain.
I can't find it.
--- me
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