On Jan 4, Prahlad Vaidyanathan said: >I tried this : > >my $text = " this is a test" ; > ># Test 1 >my $leading_spaces = ($text =~ m/^(\s+)/) ; # This doesn't work >print $leading_spaces ; # Prints 1
You have executed the regex in scalar context. Why? Because the left-hand side of the = is a single value. You can make this into a one-element list by using parentheses: my ($leading_spaces) = $text =~ /^(\s+)/; ># Test 2 >print ($text =~ m/^(\s+)/) ; # this prints the spaces print() takes a list of values, so the regex is executed in list context already. -- Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/ RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/ ** Look for "Regular Expressions in Perl" published by Manning, in 2002 ** <stu> what does y/// stand for? <tenderpuss> why, yansliterate of course. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
