Hello all. Can't figure this out...I execute the following scipt and the output of the KSH pipe is placed at the top of the log file instead of in order of when it was executed. ----------------------------------------------------------- Script looks like this: ----------------------------------------------------------- #!/usr/bin/perl my $PGPPATH = "/usr/local/pgp-6.5.1/keyrings"; my $PGP = "/usr/local/pgp-6.5.1/pgp"; open STDOUT, ">/home/michael/test1.log" or die; open STDERR, ">&STDOUT" or die; print "Beginning of script test1\n"; open KSH, "|ksh" or die; print KSH << "EOKSH"; export PGPPATH=$PGPPATH $PGP +force -e "/home/michael/file1.txt" testpgpkey EOKSH close KSH;
---------------------------------------------------------------- Log file looks like this: ---------------------------------------------------------------- Pretty Good Privacy(tm) Version 6.5.1 (c) 1999 Network Associates Inc. Uses the BSafe(tm) Toolkit, which is copyright RSA Data Security, Inc. Export of this software may be restricted by the U.S. government. Recipients' public key(s) will be used to encrypt. Key for user ID: testpgpkey 1024-bit DSS key, Key ID 0x0F031FA4, created 2001/03/15 Ciphertext file: /home/michael/file1.txt.pgp Beginning of script test1. Thank's for any help. -Michael __________________________________________________ Do You Yahoo!? Send your FREE holiday greetings online! http://greetings.yahoo.com -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
