Hi All,
I have a C program which i want to convert it into perl
In the C program it is given like this
typedef unsigned short u_int16;
#define dataLen 4
#define keyLen 52
#define userkeyLen 8
#define DataT(v) u_int16 v [dataLen]
#define keyT(v) u_int16 v [keyLen]
#define UserKeyT(v) u_int16 v [userKeyLen]
void function(DataT(dataIn), DataT(dataOut), keyT(key));
how can i convert the above lines into perl scripts, i thought that getting
the datalen from the input would solve the problem but how to get the
datalen of that variable in PERL?
Also is there a way that i can convert the datalen into binary format
is yes how?
Any one have any idea?
This is second question:
I know that if i want to XOR two data
then i have to use "^"
I have a PERL script which is like this
print "Enter number: ";
chomp($number = <STDIN>);
print "Enter another number: ";
chomp($num = <STDIN>);
$value = $number ^ $num;
print "the value is $value\n;
is there any mistake in the above script, i know it is dumb, reason i am
asking is this
it doesnt print any value and if i use xor instead of ^
$value = "$number" xor "$num"
it shows me a warning saying that useless use of xor
Where am i making mistake ?
But the first mentioned script works well for "&" and "||" but not for "^"
why though?
please enlighten me on these two aspects
:wq Prabhu
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Never write it in 'C', if you can do it in 'awk';
Never do it in 'awk', if 'sed' can handle it;
Never use 'sed' when 'tr' can do the job;
Never invoke 'tr' when 'cat' is sufficient;
Avoid using 'cat' whenever possible;
- Laws of programming.
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