Trying to alter the value of $testfile depending on how many arguments are
given, using the following:
if (@ARGV == 2) {
chdir $ARGV[0];
my $testfile = $ARGV[1];
}
else {
my $testfile = $ARGV[0];
}
I figured out what was wrong, i.e. I can't use my $testfile within the if,
giving me :
my $testfile;
if (@ARGV == 2) {
chdir $ARGV[0];
$testfile = $ARGV[1];
}
else {
$testfile = $ARGV[0];
}
which works.
Why though? Isn't the first complitation run through the script by the
interpreter, a syntax check? why would it pick up my $tesfile twice?
cheers.
ben.
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