--- Booher Timothy B 1stLt AFRL/MNAC <[EMAIL PROTECTED]> wrote:
> o.k. another regex issue . . . I want a one-liner that can remove everything
> after a given character: i.e.
>
> in this case everything after ! (fortran comment):
>
> would this work:
>
> perl -npe 's/\!.+$//'
>
> my thinking is that \! Is the literal character and . would count for
> anything + would represent any number of anything and $ would symbolize the
> end of the line. Am I close, if so how close?
>
> Thanks so much,
>
> tim
Ugh. In my previous example, I had non-capturing parens and made it optional. I had
them because
this was a slightly different regex, originally. What follows is better (with the
caveat that any
exclamation points that don't mark quotes are going to cause problems.
perl -pi.bak -e 's/!.*$//' list of files
Cheers,
Curtis "Ovid" Poe
=====
Senior Programmer
Onsite! Technology (http://www.onsitetech.com/)
"Ovid" on http://www.perlmonks.org/
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