Jeff 'Japhy' Pinyan wrote:
> 
> I suggest a negative look-behind and a negative look-ahead:
> 
>   $string =~ s/(?<!\s)\s(?!\s)//g;
> 
> But that might take too long, since it's probably not optimized the way it
> should be.  So I'd probably go with:
> 
>   $string =~ s/(\s+)/length($1) == 1 and $1/eg;
                                  ^^^^
    $string =~ s/(\s+)/length($1) != 1 and $1/eg;



John
-- 
use Perl;
program
fulfillment

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