Hi Daniel,
On Wed, Nov 28, 2001 at 11:13:59AM +1030, Daniel Falkenberg
([EMAIL PROTECTED]) said something similar to:
[snip]
> %users = (
> 'crud' => '503',
> 'test' => '45',
> 'test4' => '45',
> 'test2' => '45',
> 'daniel'=> '45'
> );
[snip]
> #Check to see if #user exists
> if ( ! defined $users{$user} ) {
> print "Sorry user $user does not exist! \n";
> }elsif (! defined $users{$user}{'45'} ) {
> print "Sorry the user $user does not have a GID of 45! \n";
> } else {
> print "Found $user! This user has a GID of 45! \n";
> }
>
> For some reason it will check the first if statement (! defined
> $users{$user}) and check this OK. But when I get to the second if
> statement ( ! defined $users{$user}{'45'} ) it will never return true no
> matter what $user is set to? I figured that ! defined
> $users{$user}{'45'} would return false if for example $user = crud, but
> if $user = test4 then it should return to the last else statement?
There is no $user{test4}{45}. If the hash looked like the following, there
would be:
%users = (
'crud' => '503',
'test' => '45',
'test4' => {45 => 'fortyfive'},
'test2' => '45',
'daniel'=> '45'
);
You really want that statement to look like:
}elsif ($users{$user} != 45) {
Cheers,
Kevin
--
[Writing CGI Applications with Perl - http://perlcgi-book.com]
And now....you are going to dance...like you've never danced before!
-- Frank Zappa
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