2018-07-17 19:56:59 +0800 Lauren C.:
> Hello,
>
> I want to match:
>
> /path/
> /path/123
> /path/abc
>
> but /path/?xxx should not be matched.
>
> This works:
>
> $ perl -le '$x="/path/abc"; print 1 if $x=~m{path/\w+}'
> 1
>
>
> this works too:
>
> $ perl -le '$x="/path/?abc"; print 1 if $x=~m{path/\w+}'
>
>
> But it doesn't work for this case:
>
> $ perl -le '$x="/path/"; print 1 if $x=~m{path/\w+}'
From "perlintro":
Quantifier * : zero or more of the previous thing.
Quantifier + : one or more of the previous thing.
So "/path/" won't match m{path/\w+} because this regex wants "one or more \w"
at that position, which the string doesn't have. If you use m{path/\w*} (note
the asterisk) then you're saying "zero or more \w" at that position, and it'll
match.
> it expects 1 returned.
>
> Can you help? thanks.
>
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