Hi,
On Wed, 28 Mar 2018 13:00:47 +0700
Olivier <olivier.nic...@cs.ait.ac.th> wrote:
> Hi,
>
> I am building a script to modify my LDAP directory and I want to use
> something like:
>
> $mesg = $ldap->modify( $dn,
> replace => {
> description => 'New List of members',
> seeAlso => 'Some reference'
> }
> );
>
> But I would like to build the list of replacements dynamically, that is,
> have a variable of the appropriate type, where I can first store
> "description" and "New List of members" then also store "seeAlso" and
> "Some reference"; and then only use that variable to do the replace.
>
please see http://perl-begin.org/topics/references/ .
> I have two questions:
>
> - What type should I use for the variable?
>
> - What will be the syntax for the $ldap->modify statement?
>
> Thanks in advance,
>
> Olivier
>
>
>
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