> -----Original Message----- > From: Frank Newland [mailto:[EMAIL PROTECTED]] > Sent: Monday, October 29, 2001 4:40 PM > To: [EMAIL PROTECTED] > Subject: Regex syntax > > > Hey, > > On an Oct 25 thread, someone asked how to remove trailing spaces. > The response was $Value =~ s/\s+$//. > > Question. > > 1. The string upon which this operation was made is on $_ correct?
No. It was on $Value (the lvalue to the left of the =~ operator) $_ is used if you leave out the =~ altogether. The following two statements are equivalent: $_ =~ s/foo/bar/; s/foo/bar/; > 2. If I've made the assignment $tempstring = substr($_ ,0,20) how do I > remove trailing spaces from $tempstring? $tempstring =~ s/\s+$//; -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
