On 10/22/2016 06:56 PM, Eric de Hont wrote:
> Op 21-10-16 om 14:13 schreef Vincent Lequertier:
>> This code creates a zip file which contains several files, all named
>> 'test'. The thing I'm trying to achieve is to have all the output of
>> commands being appended to a 'test' file, into the zip.
>>
>> How can I do this properly ? I mean without having to create a temp file
>> with a filehandle with all the output and adding the file to the zip
>> after the for loop.
> A zip-file is no compressed filesystem, so I think there is no way to do
> what you want properly.
>
> You could do something like this, but in the else block you will have
> all of your data temporarily uncompressed in memory:
>
> if (! $zip->memberNamed( 'test' )) {
> $zip->addString($config, 'test', COMPRESSION_DEFLATED);
> }
> else {
> $zip->contents( 'test', $zip->contents( 'test' ) . $config );
> }
>
> If it's too much data to fit in memory you have to go with the temp file
> option.
>
> Just a thought though: perhaps a zip archive to compress just one file
> is a bit overkill.
>
> Maybe IO::Compress::Gzip, which let's you compress strings in this way:
>
> gzip \$input \$output
>
> is better suited, or could at least be used in stead of the temp file.
>
> Greetings,
> Eric de Hont
Your approach works well, thanks. I'm ziping a lot of files by the way
(but I have only one file that needs to be a concatenation of multiple
strings in the loop). I've just shown this tiny example to highlight
what the problem was.
Thank you again
--
Vincent Lequertier
skysymbol.github.io
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
