Hello,
I don’t know whether it is possible to count the occurrence in hash?
print $var, $myhash{$var}++.”\n”;
Jing
> On 9 Feb 2016, at 14:08, James Kerwin <jkerwin2...@gmail.com> wrote:
>
> Afternoon all,
>
> I have the following problem:
>
> I have an array containing a list of non-unique strings. eg:
>
> @array Contains:
>
> 111111_
> 222222_
> 333333_
> 333333_
> 333333_
> 444444_
> 444444_
> 555555_
>
> What I would like to do is number each element of the array to look as
> follows:
>
> 111111_1
> 222222_1
> 333333_1
> 333333_2
> 333333_3
> 444444_1
> 444444_2
> 555555_1
>
> I have so far tried to use "exists", while loops and all the usual stuff as
> it seemed very simple at first. My attempts have mostly focused on equating
> the current element of the array with the previous one and asking if they are
> equal and then taking action. I just can't get the logic right though. I keep
> getting them all numbered sequentially from 1 to 10 or they all end in "_2"
> or alternating "_1" and "_2" If anybody could shed even the smallest glimmer
> of light on how to solve this I'd be really grateful.
>
> Thanks,
> James.
>
>
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