I think John has answered your immediate question.
If you want to get the files back in a particular order you should include
a sort between and grep readdir. An example might be
my @files = sort { $a cmp $b }
grep { ! /^\./ && -f "$dir/$_" } readdir($dh);
for (0..$#files) {
print "$_) $files[$_]\n";
}
Alternatively, if you want the files in size order you could use something
like this
my @files = map { $_->[0] }
sort { $a->[1] <=> $b->[1] } # numeric sort
map { [$_, -s "$dir/$_"] }
grep { ! /^\./ && -f "$dir/$_" } readdir($dh);
for (0..$#files) {
print "$_) $files[$_]\n";
}
If you want to get them back in an order based on the file modification
time, you would need to stat the file,
my @files = map { $_->[0] }
sort { $a cmp $b }
map {[$_, (stat("$dir/$_"))[9] ] }
grep { ! /^\./ && -f "$dir/$_" } readdir($dh);
Hope that helps,
Dermot.
On 9 January 2015 at 01:52, Harry Putnam <rea...@newsguy.com> wrote:
> Opening a directory and readdir with a grep in there to find specific
> filenames, how does that process collect the files?
>
> I mean will the generated @ar of files be oldest first or someother
> reliable order?
>
> Using an example paraphrased from perldoc -f readdir:
> (I changed the regex)
>
> opendir(my $dh, $some_dir) || die "can't opendir $some_dir: $!";
> my @a_ar = grep { /^a/ && -f "$some_dir/$_" } readdir($dh);
> closedir $dh;
>
> Will all the files beginning with `a' that make it to @a_ar, always be
> in order of modtime, oldest first? Or some other reliable order?
>
> Also, is there a similar reliable way files are processed when using
> File::Find?
>
> The perldoc page mentions that its depth first, but then what. What
> factors are considered in choosing a file to process?
>
> Of course, I mean beyond whatever specifications the script imposes.
>
>
>
>
>
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