On Wed, Dec 11, 2013 at 10:35 AM, punit jain <contactpunitj...@gmail.com>wrote:
>
> Thanks Shlomi, thats a good idea. However at the same time I was trying to
> understand if something is wrong in my regex. Why would $2 capture the
> number as I have used :-
>
> (?:(91\d{10}|0\d{10}|[7-9]\d{9}|0\d{11})|(?:(?:ph|cal)(\d+)))
>
> This would in my understanding match either number with regex
> 91\d{10}|0\d{10}|[7-9]\d{9}|0\d{11}
> or with call followed by digits.
>
> In my case 4 ( price for free consultation call92504060) why would $1
> store an empty string and $2 actually stores the number part ?
>
There are two sets of capturing parenthesis:
* (91\d{10}|0\d{10}|[7-9]\d{9}|0\d{11}) = $1
* (\d+) = $2
The first set stores its match in $1 and the second set in $2. The pipe
(or) does not reset the capture counter back to 1. The counter strictly
goes from left to right.
--
Robert Wohlfarth
