I think the rest after the 'if' for the last is wrong. either do this:
last if ($counter > 2);
or
if ( $counter > 2) {
print 'if : ' . $counter . "\n"; #could do print "if : $counter\n" as
well
last;
}
On Mon, Jun 17, 2013 at 8:56 AM, lee <l...@yun.yagibdah.de> wrote:
> Hi,
>
> trying to figure out what `last' actually does, I wrote this test
> script:
>
>
> use strict;
> use warnings;
> use autodie;
>
> my $counter = 0;
>
> while($counter < 8) {
> last if($counter > 2) {
> print "if: " . $counter . "\n";
> }
> else {
> print "else: " . $counter . "\n";
> }
> $counter++;
> }
>
>
> Unfortunately, that gives syntax errors. I would expect the following
> output:
>
>
> else: 0
> else: 1
> else: 2
> if: 3
>
>
> What's wrong with that (letting aside that it is terribly ambiguous)?
>
>
> --
> "Object-oriented programming languages aren't completely convinced that
> you should be allowed to do anything with functions."
> http://www.joelonsoftware.com/items/2006/08/01.html
>
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>
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