Hi,
I want to change the record separator in a Perl one liner with ">" as
the separator. However, I tried without success.
The perlrun document
(http://perldoc.perl.org/perlrun.html#Command-Switches) says that*
"***-0*[/octal/hexadecimal/] * specifies the input record separator
(|$/| ) as an octal or hexadecimal number. *"
*When I tried to get the octal/hexadecimal code of ">" with oct(">") and
hex(">"), I got "0". I used this number and it did not work the way I
wanted (perl -00 -ne 'print if /AAAA/' test.seq ).
Do the functions (oct and hex) return the octal and hexadecimal value of
the inputted character? The document on the web seems to give different
answers.
http://perldoc.perl.org/index-functions-by-cat.html#Functions-for-SCALARs-or-strings
hex <http://perldoc.perl.org/functions/hex.html> - convert a string to a
hexadecimal number
oct <http://perldoc.perl.org/functions/oct.html> - convert a string to
an octal number
http://perldoc.perl.org/functions/hex.html
*hex EXPR **hex* Interprets EXPR as a hex string and returns the
corresponding value.
http://perldoc.perl.org/functions/oct.html
*oct EXPR **oct* Interprets EXPR as an octal string and returns the
corresponding value.
I tested the functions. The first description is possibly wrong. If I am
right, which functions could be used to get the octal and hexadecimal
number of a string? How should the Perl one liner be written to change
the record sepatator to ">"? Thanks for your attention.
Dejian
