The easiest thing would be to rewrite your sql with an aggregate statement :
SELECT employee_id,date,SUM(hours_wrkd) FROM data WHERE date >= $date_then AND date <= $date_now GROUP BY empoyee_id,date ORDER BY 3 cheers. - Jose from Mexico On Thu, May 17, 2012 at 6:46 PM, Omega -1911 <1911...@gmail.com> wrote: > Hello all - > > While trying to create a script that generates a graph, I am at a loss > for a workable solution. What I need to be able to do in the code > below is add the results from the select statement before pushing the > data into an array. For example, the database contains the following > data: > > EMPLOYEE_ID - HOURS_WRKD - DATE > -------------------------------------------------------- > David - 8.5 - 1336432429 > Marty - 7.5 - 1336432429 > David - 5.0 - 1336432429 > Steve - 8.0 - 1336432429 > Elana - 6.5 - 1336432429 > Marty - 8.0 - 1336432429 > > What I need to be able to do is add the employee's total hours before > pushing it into the array. As such, the following is what would be > pushed into the arrays below: > > David - 13.5 - 1336432429 > Marty - 15.5 - 1336432429 > Steve - 8.0 - 1336432429 > Elana - 6.5 - 1336432429 > > --------%<------ACTUAL CODE ------------%<----------------- > my $dbh = DBI->connect( "dbi:SQLite:dbname=$database_name", "", "" ); > my $all = $dbh->selectall_arrayref("SELECT employee_id, hours_wrkd, > date FROM data WHERE date >= $date_then AND date <= $date_now ORDER BY > hours_wrkd DESC" ); > foreach my $row (@$all) > { > ($employee_id, $hours_wrkd, $date) = @$row; > print "\n\n$employee_id, $hours_wrkd, $date \n"; > push(@DATABASE_NAMES, $employee_id); > push(@DATABASE_HOURS, $hours_wrkd); > } > ------------------------------------------------------------------------- > Thanks for any help! - David > > -- > To unsubscribe, e-mail: beginners-unsubscr...@perl.org > For additional commands, e-mail: beginners-h...@perl.org > http://learn.perl.org/ > > >