On 12-01-31 01:11 PM, Matt wrote:
When I copy a hash like so:
my %hash2 = %hash1;
Modifying hash2 seems to modify hash1. How do I make it so there both
independent after being copied?
This creates a shallow copy. It does not copy the contents of any
references in the hash. To do that, use dclone() from Storable.
use Storable qw( dclone );
%hash2 = %{ dclone( \%hash1 ) };
See `perldoc Storable` for details.
--
Just my 0.00000002 million dollars worth,
Shawn
Programming is as much about organization and communication
as it is about coding.
Strength is not a measure of the body.
It's a measure of the heart.
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