On Tue, Aug 16, 2011 at 8:27 PM, Joseph L. Casale <jcas...@activenetwerx.com > wrote:
> What is the correct way to quickly assign the result of a regex against > a cmdline arg into a new variable: > > my $var = ($ARGV[0] =~ s/(.*)foo/$1/i); > > Obviously that's incorrect but is there a quick way without intermediate > assignment? > > Thanks! > jlc > > -- > To unsubscribe, e-mail: beginners-unsubscr...@perl.org > For additional commands, e-mail: beginners-h...@perl.org > http://learn.perl.org/ > > > Hi Joseph, I would suggest naming your selectors like so: $ARGV[0] =~ s/(?'string'.*)foo/$1/i; Now you can access this variable by simply using $+{string} as your variable. That way you can identify your variables directly and assign them meaningful names. Certainly in a more complex regular expressions with many variables being retrieved this can be very useful. Of course the draw back is that on the next regular expression this $+{<whatever>} will get reset and you will loose what ever you retrieved similar to $1 etc... Regards, Rob
