>>>>> "PD" == Patrick Dupre <patrick.du...@york.ac.uk> writes:
PD> On Sun, 19 Jun 2011, Uri Guttman wrote:
>> use bignum;
>>
>> $x = 2 + 4.5,"\n"; # BigFloat 6.5
>>
>> {
>> no bignum;
>> print 2 ** 256,"\n"; # a normal Perl scalar now
>> }
>>
PD> This is what I tried first, the point is when you quite the
PD> enclosure, even if you use no bignum, since the variables have declared
PD> previous as bignumn any calculation using such variables previous
PD> declared as bignum will be store in variables of the same type.
PD> This make sense for perl, only a cast should allow changing the size.
PD> In addition, the physical size (SV) of a bignum seems a lot bigger
PD> than a usual NV.
as rob said, you can always sprintf the bignum and then numify it into a
regular float (where bignum isn't in effect). slow but it should work
unless the bignum exponent is actually larger than any supported float
can handle.
uri
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