On 14/05/2011 08:57, Agnello George wrote:
I got a string like this
$string = ' [a b c d]'
i need to get a b c d in to a array called @all.
i was was trying to so a split with delimiter '\s+' but still i get
[a
b
c
d]
but i want
a
b
c
d
any idea how to get this done , thanks
By the way, a call to split with a single space string as the pattern is
a special case. It is the default if no pattern is provided, and more
than likely what you want. This is from perldoc -f split
As a special case, specifying a PATTERN of space (' ') will split on
white space just as "split" with no arguments does. [...] A "split"
on "/\s+/" is like a "split(' ')" except that any leading whitespace
produces a null first field. A "split" with no arguments really does
a "split(' ', $_)" internally.
I am sure the problem is more complex han you describe, but to be safe
why not just remove the brackets before you do the split? A working
program below.
HTH,
Rob
use strict;
use warnings;
my $string = ' [a b c d]';
$string =~ tr/[]//d;
my @contents = split ' ', $string;
print "$_\n" foreach @contents;
**OUTPUT**
a
b
c
d
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