On Oct 2, Bob Showalter said: >> -----Original Message----- >> From: eric [mailto:[EMAIL PROTECTED]] >> >> show how to creat a random number inthe following range: >> 5 to 15 >> -10 to 20 >> >> the documentation for rand and srand are not too useful. > >Well, they're extremely useful in telling what those routines >do, so I don't understand your complaint. > >Anyway, since rand(x) generates a random number in the range >0 <= n < x, it should be trivial to map that to the range >a <= n < b, right?
Yes, the rand() function returns some value greater than or equal to 0 and less than the value you pass it (which defaults to 1). If you want an integer in the range from 0 to $N - 1, you would do: $val = int rand($N); If you then want an interger in the range from 1 to $N, you'd add 1 to the RETURNED value: $val = 1 + int rand($N); Use this to figure out how to shift the ranges to get numbers from 5 to 15 and -10 to 20. 0 <= rand(N) < N 0 + A <= rand(N) + A < N + A -- Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/ RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/ ** Look for "Regular Expressions in Perl" published by Manning, in 2002 ** -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
