There was a typo in my original email. I missed the word "not" which was very
crucial as always.
Scenario: #1
unless ( (defined $result) && ($test !~ /TEST/) )
{ my $result = "OK";
print "$result\n";
}
I thought it was:
UNLESS $result is defined and UNLESS $test does not contain TEST = IF $result
is not defined and if $test contains TEST.
Scenario: #2
unless (defined $result)
{
unless ($test !~ /TEST/)
{ my $result = "OK";
print "$result\n";
}
}
This would work as I thought (UNLESS $result is defined and UNLESS $test does
not contain TEST), but not the scenario #1.
Regards,
Akhthar Parvez K
http://Tips.SysAdminGUIDE.COM
UNIX is basically a simple operating system, but you have to be a genius to
understand the simplicity - Dennie Richie
On Thursday 29 Apr 2010, Akhthar Parvez K wrote:
> Hi,
>
> Could someone explain this condition:
>
> Scenario: #1
> unless ( (defined $result) && ($test !~ /TEST/) )
> { my $result = "OK";
> print "$result\n";
> }
>
> I thought it was:
> UNLESS (IF NOT) $result is defined and UNLESS (IF NOT) $test does contain TEST
>
> But that doesn't seem to be the case.
>
> I find it strange to learn that the below condition is not the same:
>
> Scenario: #2
> unless (defined $result)
> {
> unless ($test !~ /TEST/)
> { my $result = "OK";
> print "$result\n";
> }
> }
>
> This would work as I thought (UNLESS $result is defined and UNLESS $test does
> contain TEST), but not the scenario #1.
>
> Regards,
> Akhthar Parvez K
> http://Tips.SysAdminGUIDE.COM
> UNIX is basically a simple operating system, but you have to be a genius to
> understand the simplicity - Dennie Richie
>
