CHAN, KENNETH 1 [AG/7721] wrote:
Hi all,
Hello,
I have 2 simple questions (maybe be very trial): 1. I saw some code put "umask 022;" in the near beginning of perl script. I understand that umask is for changing the file permission in unix/linux.
No, that is incorrect. umask() by itself does not change a file. man 2 umask NAME umask - set file mode creation mask SYNOPSIS #include <sys/types.h> #include <sys/stat.h> mode_t umask(mode_t mask); DESCRIPTION umask() sets the calling process’s file mode creation mask (umask) to mask & 0777 (i.e., only the file permission bits of mask are used), and returns the previous value of the mask. The umask is used by open(2), mkdir(2), and other system calls that create files to modify the permissions placed on newly created files or directories. Specifically, permissions in the umask are turned off from the mode argument to open(2) and mkdir(2). The constants that should be used to specify mask are described under stat(2). The typical default value for the process umask is S_IWGRP | S_IWOTH (octal 022). In the usual case where the mode argument to open(2) is specified as: S_IRUSR | S_IWUSR | S_IRGRP | S_IWGRP | S_IROTH | S_IWOTH (octal 0666) when creating a new file, the permissions on the resulting file will be: S_IRUSR | S_IWUSR | S_IRGRP | S_IROTH (because 0666 & ~022 = 0644; i.e., rw-r--r--). John -- The programmer is fighting against the two most destructive forces in the universe: entropy and human stupidity. -- Damian Conway -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/