> -----Original Message----- > From: Grant [mailto:emailgr...@gmail.com] > Sent: Tuesday, April 21, 2009 12:43 > To: Perl Beginners List > Subject: Re: String manipulation question > > >> >> Thanks guys. With some help I've come up with this: > >> >> > >> >> $string = 'abc def ghi jkl mno pqr stu vwx yz'; > >> >> if(length($string) = 34) {$var1 = $string.":";} > >> > > >> > '=' is assignment, '==' is test for numerical equality. > >> Change the above > >> > line to: > >> > if( length($string) == 34 ) { $var1 = $string . ':' } > >> > > >> >> if(length($string) > 34) { > >> >> $string =~ s/\s//g; > >> > > >> > The above line deletes all of the spaces in $string. Is > >> that what you want > >> > to do? > >> > >> All fixed up except for this. How can I remove only the > spaces at the > >> end of $var1 and $var2 if they exist? > >> > >> - Grant > >> > >> > >> >> ($var1, $var2) = $string =~ /(.){35}(.){26}/; > >> > > > This pulls 35 characters and splits words, yet what > you asked for was the last word separated. Correct? > > I'm trying to pull 35 or fewer characters to the nearest space > basically. This is what I have now: > > if(length($string) <= 34) {$var1 = $string.":";} > if(length($string) > 34) { > ($var1, $var2) = ($string =~ /(.{35})(.{26})/); 1234567891124567892123456789312345 if you have in $string = q[1234 12345 12 5346 12367 123 123678123]; Then $var1 will be '1234 12345 12 5346 12367 123 12367', but I thought you wanted '1234 12345 12 5346 12367 123'? Which one is the right one for what you are doing? Wags ;)
> $var1 =~ s/\s+$//; > $var2 =~ s/\s+$//; > $var2 .= ":"; > } > > Does that look OK? Is the 3rd line off? > > - Grant > > -- > To unsubscribe, e-mail: beginners-unsubscr...@perl.org > For additional commands, e-mail: beginners-h...@perl.org > http://learn.perl.org/ > > > -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/
