This worked fine for me!
$_ = "nobody Wed Aug 22 12:32:22 2001 I";
print "$_\n";
$_ =~ s/^(.{7})\s+?(.{24})\s+?(\S+)$/$1,$2,$3/;
print "User = $1\n";
print "Date = $2\n";
print "State = $3\n";
John Way
GoodleafJ@imm
unex.com To: [EMAIL PROTECTED]
cc:
09/04/2001 Subject: regex: can't match pattern...
dang
01:10 PM
I posted a similar question last week; this is a rephrasing.
I have the following strings:
root Wed Aug 22 04:44:59 2001 DLs
root Wed Aug 22 04:44:59 2001 ILs
root Wed Aug 22 04:44:59 2001 DL
root Wed Aug 22 04:44:59 2001 DL
root Wed Aug 22 04:44:59 2001 DL
root Wed Aug 22 04:44:59 2001 DL
root Wed Aug 22 04:46:37 2001 Is
root Wed Aug 22 11:46:38 2001 Ss
root Wed Aug 22 11:46:39 2001 Ss
daemon Wed Aug 22 11:46:40 2001 Is
root Wed Aug 22 11:46:41 2001 Is
root Wed Aug 22 11:46:41 2001 Ss
root Wed Aug 22 11:46:41 2001 Is
root Wed Aug 22 12:31:21 2001 Is
postfix Wed Aug 22 12:31:21 2001 I
root Wed Aug 22 12:32:21 2001 Ss
nobody Wed Aug 22 12:32:21 2001 I
nobody Wed Aug 22 12:32:22 2001 I
nobody Wed Aug 22 12:32:22 2001 I
nobody Wed Aug 22 12:32:22 2001 I
I want three things:
user, the entire date, the state.
I'm currently trying to get this with:
for(@procs){
/^(.{7})\s+?(.{24})\s+?(\S+?)$/;
I want $1 to be the user (e.g. 'root' 'postfix').
I want $2 to be something like 'Wed Aug 23 05:30:01 2001'.
I want $3 to be the state, which was a lot of forms, but which is, for
example 'DLs' above.
Shouldn't this get the first 7, then 24 characters, then the glop that's
left over?
What am I doing wrong?
-John
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